The isomorphism theorems describe important relationships among homomorphisms, normal subgroups, quotient groups, and images of groups.
First Isomorphism Theorem
Theorem: Let
\[\psi:G\rightarrow G'\]
be a group homomorphism. Then \(\ker\psi\) is a normal subgroup of \(G\), and
\[\frac{G}{\ker\psi}\cong\operatorname{Im}\psi.\]
In particular, if \(\psi\) is surjective, then \(\operatorname{Im}\psi=G'\), and hence
\[\frac{G}{\ker\psi}\cong G'.\]
The isomorphism is given by
\[x\ker\psi\longmapsto\psi(x).\]
This theorem states that the image of a homomorphism is isomorphic to the domain group after the kernel has been factored out.
Second Isomorphism Theorem
Theorem: Let \(H\) and \(K\) be subgroups of a group \(G\), and suppose that \(K\) is normal in \(G\). Then \(H\cap K\) is normal in \(H\), \(HK\) is a subgroup of \(G\), and
\[\frac{H}{H\cap K}\cong\frac{HK}{K}.\]
The corresponding isomorphism is induced by the homomorphism
\[\phi:H\rightarrow\frac{HK}{K},\qquad \phi(h)=hK.\]
Its kernel is \(H\cap K\), and its image is \(HK/K\). Therefore, the result follows from the First Isomorphism Theorem.
Third Isomorphism Theorem
Theorem: Let \(H\) and \(K\) be normal subgroups of a group \(G\) such that
\[H\subseteq K.\]
Then \(K/H\) is a normal subgroup of \(G/H\), and
\[\frac{G/H}{K/H}\cong\frac{G}{K}.\]
This theorem is sometimes called the quotient of a quotient theorem. It shows that first factoring \(G\) by \(H\) and then factoring the resulting group by \(K/H\) gives, up to isomorphism, the same result as factoring \(G\) directly by \(K\).
Maximal Normal Subgroup
Let \(G\) be a group. A normal subgroup \(N\) of \(G\) is called a maximal normal subgroup of \(G\) if the following conditions hold:
- \(N\neq G\).
- If \(M\) is a normal subgroup of \(G\) such that \[N\subseteq M\subseteq G,\] then either \(M=N\) or \(M=G\).
Thus, a maximal normal subgroup is a proper normal subgroup that is not properly contained in any other proper normal subgroup of \(G\).
Simple Group
A nontrivial group \(G\) is called a simple group if its only normal subgroups are
\[\{e\}\quad\text{and}\quad G.\]
Equivalently, a nontrivial group is simple if it has no nontrivial proper normal subgroup.
Maximal Normal Subgroups and Simple Quotients
Corollary: Let \(N\) be a proper normal subgroup of \(G\). Then \(N\) is a maximal normal subgroup of \(G\) if and only if the quotient group \(G/N\) is simple.
This result provides a useful criterion for determining whether a normal subgroup is maximal.
Intersection of Distinct Maximal Normal Subgroups
Corollary: Let \(H\) and \(K\) be distinct maximal normal subgroups of \(G\). Then:
- \(HK=G\).
- \(H\cap K\) is a maximal normal subgroup of \(H\).
- \(H\cap K\) is a maximal normal subgroup of \(K\).
Indeed, by the Second Isomorphism Theorem,
\[\frac{H}{H\cap K}\cong\frac{G}{K}\]
and
\[\frac{K}{H\cap K}\cong\frac{G}{H}.\]
Since \(G/K\) and \(G/H\) are simple, \(H\cap K\) is maximal normal in both \(H\) and \(K\).